Change of variables (PDE)

From Wikipedia, the free encyclopedia

Jump to: navigation, search
Topics in calculus

Fundamental theorem
Limits of functions
Continuity
Vector calculus
Matrix calculus
Mean value theorem

Differentiation

Product rule
Quotient rule
Chain rule
Change of variables
Implicit differentiation
Taylor's theorem
Related rates
List of differentiation identities

Integration

Lists of integrals
Improper integrals
Integration by:
parts, disks, cylindrical
shells
, substitution,
trigonometric substitution,
partial fractions, changing order

Often a partial differential equation can be reduced to a simpler form with a known solution by a suitable change of variables.

The article below discusses change of variable for PDEs in two ways:

  1. By example
  2. By giving the theory of the method

Contents

[edit] Technique explained by example

For example the following simplified form of the Black–Scholes PDE

 \frac{\partial V}{\partial t} + \frac{1}{2} S^2\frac{\partial^2 V}{\partial S^2} + S\frac{\partial V}{\partial S} - V = 0.

is reducible to the Heat equation

 \frac{\partial u}{\partial \tau} = \frac{\partial^2 u}{\partial x^2}

by the change of variables[1]:

V(S,t) = v(x(S),τ(t))
x(S) = ln(S)
 \tau(t) = \frac{1}{2} (T - t)
v(x,τ) = exp( − (1 / 2)x − (9 / 4)τ)u(x,τ)

in these steps:

  • Replace V(S,t) by v(x(S),τ(t)) and apply the chain rule to get
\frac{1}{2}(-2v(s,\tau)+2 \frac{\partial\tau}{\partial t} \frac{\partial v}{\partial \tau} +S\left(\left(2 \frac{\partial x}{\partial S} + S\frac{\partial^2 x}{\partial S^2}\right) 
\frac{\partial v}{\partial x} + 
S \left(\frac{\partial x}{\partial S}\right)^2 \frac{\partial^2 v}{\partial x^2}\right)=0.
  • Replace x(S) and τ(t) by ln(S) and \frac{1}{2}(T-t) to get
\frac{1}{2}(
  -2v(\ln(S),\frac{1}{2}(T-t))
  -\frac{\partial v(\ln(S),\frac{1}{2}(T-t))}{\partial\tau}
  +\frac{\partial v(\ln(S),\frac{1}{2}(T-t))}{\partial x}
  +\frac{\partial^2 v(\ln(S),\frac{1}{2}(T-t))}{\partial x}.
  • Replace ln(S) and \frac{1}{2}(T-t) by x(S) and τ(t) and divide both sides by \frac{1}{2} to get
-2 v-\frac{\partial v}{\partial\tau}+\frac{\partial v}{\partial x}+ \frac{\partial^2 v}{\partial x^2}=0.
  • Replace v(x,τ) by exp( − (1 / 2)x − (9 / 4)τ)u(x,τ) and divide through by − exp( − (1 / 2)x − (9 / 4)τ)u(x,τ) to yield the heat equation.

Advice on the application of change of variable to PDEs is given by mathematician J. Michael Steele[2]:

"There is nothing particularly difficult about changing variables and transforming one equation to another, but there is an element of tedium and complexity that slows us down. There is no universal remedy for this molasses effect, but the calculations do seem to go more quickly if one follows a well-defined plan. If we know that V(S,t) satisfies an equation (like the Black-Scholes equation) we are guaranteed that we can make good use of the equation in the derivation of the equation for a new function v(x,t) defined in terms of the old if we write the old V as a function of the new v and write the new t and x as functions of the old t and S. This order of things puts everything in the direct line of fire of the chain rule; the partial derivatives \frac{\partial V}{\partial t}, \frac{\partial V}{\partial S} and \frac{\partial^2 V}{\partial S^2}are easy to compute and at the end, the original equation stands ready for immediate use."

[edit] Technique in general

Suppose that we have a function u(x,t) and a change of variables x1,x2 such that there exist functions a(x,t),b(x,t) such that

x1 = a(x,t)
x2 = b(x,t)

and functions e(x1,x2),f(x1,x2) such that

x = e(x1,x2)
t = f(x1,x2)

and furthermore such that

x1 = a(e(x1,x2),f(x1,x2))
x2 = b(e(x1,x2),f(x1,x2))

and

x = e(a(x,t),b(x,t))
t = f(a(x,t),b(x,t))

In other words, it is helpful for there to be a bijection between the old set of variables and the new one, or else one has to

  • Restrict the domain of applicability of the correspondence to a subject of the real plane which is sufficient for a solution of the practical problem at hand (where again it needs to be a bijection), and
  • Enumerate the (zero or more finite list) of exceptions (poles) where the otherwise-bijection fails (and say why these exceptions don't restrict the applicability of the solution of the reduced equation to the original equation)

If a bijection does not exist then the solution to the reduced-form equation will not in general be a solution of the original equation.

We are discussing change of variable for PDEs. A PDE can be expressed as a differential operator applied to a function. Suppose \mathcal{L} is a differential operator such that

\mathcal{L}u(x,t)=0

Then it is also the case that

\mathcal{L}v(x_1,x_2)=0

where

v(x1,x2) = u(e(x1,x2),f(x1,x2))

and we operate as follows to go from \mathcal{L}u(x,t)=0 to \mathcal{L}v(x_1,x_2)=0:

  • Apply the chain rule to \mathcal{L} v(x_1(x,t),x_2(x,t))=0 and expand out giving equation e1.
  • Substitute a(x,t) for x1(x,t) and b(x,t) for x2(x,t) in e1 and expand out giving equation e2.
  • Replace occurrences of x by e(x1,x2) and t by f(x1,x2) to yield \mathcal{L}v(x_1,x_2)=0, which will be free of x and t.

[edit] Action-angle coordinates

Often, theory can establish the existence of a change of variables, although the formula itself cannot be explicitly stated. For a integrable Hamiltonian system of dimension n, with  \dot{x}_i = \partial H/\partial p_j and  \dot{p}_j = - \partial H/\partial x_j , there exist n integrals Ii. There exists a change of variables from the coordinates  \{ x_1, \dots, x_n, p_1, \dots, p_n \} to a set of variables  \{ I_1, \dots I_n, \varphi_1, \dots, \varphi_n \} , in which the equations of motion become  \dot{I}_i = 0 ,  \dot{\varphi}_i = \omega_i(I_1, \dots, I_n) , where the functions  \omega_1, \dots, \omega_n are unknown, but depend only on  I_1, \dots, I_n . The variables  I_1, \dots, I_n are the action coordinates, the variables  \varphi_1, \dots, \varphi_n are the angle coordinates. The motion of the system can thus be visualized as rotation on torii. As a particular example, consider the simple harmonic oscillator, with  \dot{x} = 2p and  \dot{p} = - 2x , with Hamiltonian H(x,p) = x2 + p2. This system can be rewritten as  \dot{I} = 0 ,  \dot{\varphi} = 1 , where I and  \varphi are the canonical polar coordinates: I = p2 + q2 and  \tan(\varphi) = p/x . See V. I. Arnold, `Mathematical Methods of Classical Mechanics', for more details.[3]

[edit] References

  1. ^ Solution of the Black Scholes Equation
  2. ^ J. Michael Steele, Stochastic Calculus and Financial Applications, Springer, New York, 2001
  3. ^ V. I. Arnold, Mathematical Methods of Classical Mechanics, Graduate Texts in Mathematics, v. 60, Springer-Verlag, New York, 1989
Personal tools